Back to Questions
NEET Chemistry
QUESTION #7366
Question 1
Given Planck's constant \(h = 6.63 \times 10^{-34}\) Js and speed of light \(c = 3 \times 10^{17}\) nm s\(^{-1}\), the wavelength (in nm) of a quantum of light with frequency \(6 \times 10^{15}\) s\(^{-1}\) closest to:
Correct Answer Explanation
Formula: \(\lambda = \dfrac{c}{\nu}\)
\(\lambda = \dfrac{3 \times 10^{17} \text{ nm s}^{-1}}{6 \times 10^{15} \text{ s}^{-1}} = 50\) nm
This wavelength (50 nm) lies in the extreme UV (EUV) region. Note: \(c = 3\times10^8\) m/s \(= 3\times10^{17}\) nm/s.
\(\lambda = \dfrac{3 \times 10^{17} \text{ nm s}^{-1}}{6 \times 10^{15} \text{ s}^{-1}} = 50\) nm
This wavelength (50 nm) lies in the extreme UV (EUV) region. Note: \(c = 3\times10^8\) m/s \(= 3\times10^{17}\) nm/s.
Sign in to join the conversation and share your thoughts.
Log In to Comment