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NEET Chemistry QUESTION #7367
Question 1
Based on the energy equation \(E = -2.178 \times 10^{-18} \text{ J} \left(\dfrac{Z^2}{n^2}\right)\), which conclusion is INCORRECT?
  • For \(n=1\), the electron has more negative energy than at \(n=6\), so it is more loosely bound in the smallest orbit✔️
  • The negative sign means energy of bound electron is lower than that of a free electron at infinite distance
  • Larger \(n\) means larger orbital radius
  • This equation can calculate energy change during electron transitions
Correct Answer Explanation
Analysing option (1):
At \(n=1\), \(E\) is most negative (\(-2.178 \times 10^{-18}\) J for H). Most negative = most tightly bound (lowest energy state). Saying it is loosely bound is WRONG — it is the most tightly bound state.

The other statements are all correct interpretations of the Bohr energy equation. The electron at \(n=1\) is hardest to remove (highest ionisation energy).