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NEET Chemistry
QUESTION #7372
Question 1
A magnetic moment of 2.83 BM is exhibited by which of the following ions? (At. nos: Ti = 22, Cr = 24, Mn = 25, Ni = 28)
Correct Answer Explanation
Formula: \(\mu = \sqrt{n(n+2)}\) BM, where \(n\) = number of unpaired electrons.
For \(\mu = 2.83\) BM: \(2.83 = \sqrt{n(n+2)}\) ā \(n = 2\)
Checking \(\text{Ni}^{2+}\): Ni (Z=28) = [Ar] 3dāø 4sĀ². \(\text{Ni}^{2+}\) = [Ar] 3dāø ā 2 unpaired electrons ā \(\mu = \sqrt{2 \times 4} = \sqrt{8} \approx 2.83\) BM ā
For \(\mu = 2.83\) BM: \(2.83 = \sqrt{n(n+2)}\) ā \(n = 2\)
Checking \(\text{Ni}^{2+}\): Ni (Z=28) = [Ar] 3dāø 4sĀ². \(\text{Ni}^{2+}\) = [Ar] 3dāø ā 2 unpaired electrons ā \(\mu = \sqrt{2 \times 4} = \sqrt{8} \approx 2.83\) BM ā
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