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NEET Chemistry QUESTION #7396
Question 1
The correct order of electronegativity for hybrid orbitals of carbon is:
  • \(\text{sp} < \text{sp}^2 < \text{sp}^3\)
  • \(\text{sp} > \text{sp}^2 < \text{sp}^3\)
  • \(\text{sp} > \text{sp}^2 > \text{sp}^3\)✔️
  • \(\text{sp} < \text{sp}^2 > \text{sp}^3\)
Correct Answer Explanation
Electronegativity of carbon hybrid orbitals:
Greater s-character → higher electronegativity (s-electrons are held closer to nucleus).
  • sp: 50% s-character
  • sp²: 33% s-character
  • sp³: 25% s-character
Therefore: sp > sp² > sp³ in electronegativity. This also explains why sp C–H bonds (alkynes) are more acidic than sp³ C–H bonds (alkanes).