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EEJ MAIN Chemistry
QUESTION #7510
Question 1
A car tyre is filled with nitrogen gas at 35 psi at 27°C. The tyre will burst if pressure exceeds 40 psi. At what temperature (in °C) will the tyre burst?
Correct Answer Explanation
At constant volume: $\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}$ (Gay-Lussac's Law)
$P_1 = 35\ \text{psi},\ T_1 = 27 + 273 = 300\ \text{K}$
$P_2 = 40\ \text{psi}$
$T_2 = T_1 \times \dfrac{P_2}{P_1} = 300 \times \dfrac{40}{35} = 300 \times 1.1\overline{428} \approx 342.86\ \text{K}$
$T_2\ (°C) = 342.86 - 273 \approx \mathbf{72}°\text{C}$
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