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EEJ MAIN Chemistry QUESTION #7511
Question 1

3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. Find the volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K.
$[R = 0.0821\ \text{L atm K}^{-1}\ \text{mol}^{-1}]$

  • 2.00 L/g✔️
  • 4.00 L/g
  • 1.60 L/g
  • 2.40 L/g
Correct Answer Explanation

Molar mass of O$_2 = 32\ \text{g/mol}$. Moles of O$_2 = \dfrac{3.12}{32} = 0.0975\ \text{mol}$

Total volume at 1 atm, 300 K: $V = \dfrac{nRT}{P} = \dfrac{0.0975 \times 0.0821 \times 300}{1} \approx 2.40\ \text{L}$

Volume per gram of adsorbent (Pt) $= \dfrac{2.40}{1.2} = \mathbf{2.00}\ \text{L g}^{-1}$