1 g of a carbonate M_2CO_3 reacts with excess HCl and produces 0.01186 mol of CO_2. What is the molar mass of M_2CO_3 (in g mol^ -1 )?

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EEJ MAIN Chemistry QUESTION #7520

Question 1

1 g of a carbonate M$_2$CO$_3$ reacts with excess HCl and produces 0.01186 mol of CO$_2$. What is the molar mass of M$_2$CO$_3$ (in g mol$^{-1}$)?

Correct Answer Explanation

From the reaction: M$_2$CO$_3 + 2\text{HCl} \to 2\text{MCl} + \text{H}_2\text{O} + \text{CO}_2$

1 mol M$_2$CO$_3$ produces 1 mol CO$_2$.

Moles of M$_2$CO$_3 =$ moles of CO$_2 = 0.01186\ \text{mol}$

Molar mass $= \dfrac{1\ \text{g}}{0.01186\ \text{mol}} \approx \mathbf{84.3\ \text{g mol}^{-1}}$