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EEJ MAIN Chemistry QUESTION #7532
Question 1

K$_2$HgI$_4$ is 40% ionized in aqueous solution. What is the van't Hoff factor ($i$)?

  • 1.6
  • 1.8✔️
  • 2
  • 2.2
Correct Answer Explanation

K$_2$HgI$_4$ dissociates as: $\text{K}_2\text{HgI}_4 \to 2\text{K}^+ + \text{HgI}_4^{2-}$ (3 particles total if fully ionized)

Degree of ionization $\alpha = 0.40$, total particles per formula unit if fully ionized = 3.

$i = 1 + (n-1)\alpha = 1 + (3-1)(0.40) = 1 + 0.80 = \mathbf{1.80}$