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Basic Mathematics QUESTION #7652
Question 1
Three years ago, the age of a father was three times the age of his son. If the sum of their current ages is 70 years, what is the present age of the son?
  • \(20\) years
  • \(25\) years
  • \(21\) years
  • None of these✔️
Correct Answer Explanation
Let current age of son = \(x\) and father = \(y\). Given: \(x + y = 70\). Three years ago: \((y-3) = 3(x-3)\). Expanding: \(y - 3 = 3x - 9\), so \(y = 3x - 6\). Substituting in first equation: \(x + 3x - 6 = 70\), giving \(4x = 76\), so \(x = 19\) years. The answer should be 19 years, but this doesn't match the options, suggesting 'None of these' is correct.