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MDCAT Chemistry QUESTION #7824
Question 1

How many grams of CO₂ are produced by thermally decomposing 10 moles of ZnCO₃? \(\mathrm{ZnCO_3 \rightarrow ZnO + CO_2}\)

  • 320 g
  • 360 g✔️
  • 400 g
  • 440 g
Correct Answer Explanation

1 mol ZnCO₃ → 1 mol CO₂. Molar mass CO₂ = 44 g/mol. Mass = 10 × 44 = 440 g. Option d (440 g).