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Basic Mathematics
QUESTION #7994
Question 1
\(18\tfrac{1}{6} \div 2\tfrac{1}{3} = ?\)
Correct Answer Explanation
\(18\tfrac{1}{6} = \dfrac{109}{6}\) and \(2\tfrac{1}{3} = \dfrac{7}{3}\)
\(\dfrac{109}{6} \div \dfrac{7}{3} = \dfrac{109}{6} \times \dfrac{3}{7} = \dfrac{327}{42} = \dfrac{109}{14} = 7\tfrac{11}{14}\)
\(\dfrac{109}{6} \div \dfrac{7}{3} = \dfrac{109}{6} \times \dfrac{3}{7} = \dfrac{327}{42} = \dfrac{109}{14} = 7\tfrac{11}{14}\)
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