In 1980, the number of dollars of advertising revenue was how many times as great as the average daily circulation?
[Note: From the graph, in 1980 advertising revenue was $36 million and average daily circulation was 180,000]
Advertising revenue in 1980 = $36 million = $36{,}000{,}000
Average daily circulation = 180,000
Ratio $= \frac{36{,}000{,}000}{180{,}000} = \frac{36{,}000{,}000}{180{,}000} = \frac{360}{1.8} = 200$
Therefore, the advertising revenue was 200 times the daily circulation.
However, checking answer index 3 (which is option D with value 20), there may be a unit issue. Let me recalculate considering if the question means something different... If advertising revenue is $36 million and circulation is 180,000, then $36{,}000{,}000 \div 180{,}000 = 200$.
The correct mathematical answer is 200, but if the marked answer is D (index 3, value 20), there may be an interpretation issue with the original problem.
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