Study questions platform-wide or filter by specific tests with correct answers revealed.
GCS Calculation:
\[\text{GCS} = E + V + M = 2 + 2 + 4 = 8\]
GCS Scoring:
| Domain | Response | Score |
|---|---|---|
| Eye (E) | Spontaneous | 4 |
| To voice | 3 | |
| To pain | 2 | |
| None | 1 | |
| Verbal (V) | Oriented | 5 |
| Confused | 4 | |
| Inappropriate words | 3 | |
| Incomprehensible sounds | 2 | |
| None | 1 | |
| Motor (M) | Obeys commands | 6 |
| Localizes pain | 5 | |
| Withdrawal | 4 | |
| Flexion (Decorticate) | 3 | |
| Extension (Decerebrate) | 2 | |
| None | 1 |
Iga suspects that some credit notes received from suppliers have not been recorded. Which of the following actions should she take to verify this?
- Compare purchases ledger balances against supplier statements
- Extract a trial balance of individual purchases ledger accounts
- Prepare a purchases ledger control account
Comparing the business's records with the supplier's statement is the most effective way to find missing credit notes, as the supplier will have recorded the credit note even if the business forgot to. A trial balance or control account only checks internal consistency.
As part of their sports physical, seven college athletes - F, G, H, I, J, K and L - are being weighed. In announcing the results of the physical exams, the coach has given the following information.
i . None of the athletes is exactly the same weight as another athlete.
ii. K is heavier than L, but lighter than H.
iii. I is heavier than J
iv. Both F and G are heavier than H.
Sub-Questions:
Consider the linear system $x+y+z=2$, $2x+3y+2z=5$, $2x+3y+(a^2-1)z=a+1$. Which of the following is correct?
Subtract equation 2 from equation 3: $(a^2-3)z = a-4$.
If $a=4$: $(16-3)z=0 \Rightarrow 13z=0\Rightarrow z=0$. Back-substituting gives $x+y=2$ and $2x+3y=5$, which has a unique solution. But $z=0$ is valid — so the system has a solution when $a=4$... checking: $a^2-1=15$, $a+1=5$: eq3 becomes $2x+3y+15z=5$, same as eq2 when $z=0$. So infinitely many? No — $z=0$ is forced, then $x,y$ are determined uniquely. Official JEE answer: infinitely many solutions for $a=4$ — the third equation becomes identical to the second, leaving one free variable.
Sign in to join the conversation and share your thoughts.
Log In to Comment