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Suppose $x, y, z$ are in arithmetic progression (A.P.) and $\tan^{-1}x,\ \tan^{-1}y,\ \tan^{-1}z$ are also in A.P. Then:
If $\tan^{-1}x, \tan^{-1}y, \tan^{-1}z$ are in A.P., then $2\tan^{-1}y=\tan^{-1}x+\tan^{-1}z$.
Also $x,y,z$ in A.P. means $2y=x+z$.
From $2\tan^{-1}y=\tan^{-1}x+\tan^{-1}z$: using the addition formula, $\tan(2\tan^{-1}y)=\tan(\tan^{-1}x+\tan^{-1}z)$, i.e., $\dfrac{2y}{1-y^2}=\dfrac{x+z}{1-xz}$.
Substituting $x+z=2y$: $\dfrac{2y}{1-y^2}=\dfrac{2y}{1-xz}$. So $1-y^2=1-xz$, giving $y^2=xz$.
Combined with $x+z=2y$ (A.P.) and $y^2=xz$ (G.P.) $\Rightarrow x=y=z$.
ΩΨ³ΩΫ Ψ§ΨΉΨͺΨ¨Ψ§Ψ± Ψ³Ϋ ΩΩΨΈ Ψ§Ψ±Ψ―Ω Ϊ©Ψ³ Ψ²Ψ¨Ψ§Ω Ϊ©Ψ§ ΩΩΨΈ ΫΫΨ
- \(408 = 2^3 \times 3 \times 17\)
- \(462 = 2 \times 3 \times 7 \times 11\)
- \(516 = 2^2 \times 3 \times 43\)
This scenario describes Fetal Distress in the Second Stage of labor:
- Late decelerations = uteroplacental insufficiency (ominous)
- Reduced variability = compromised fetal CNS oxygenation
- Fetal scalp pH 7.19 = Pre-acidosis/borderline acidosis (Normal: \(\geq 7.25\); Borderline: \(7.20{-}7.24\); Acidosis: \(<7.20\))
Since the patient is in the second stage with a deliverable presenting part, and no absolute contraindications:
- Operative vaginal delivery (forceps/vacuum) is faster and safer than CS in second stage.
- CS is reserved if operative delivery is not feasible (high station, asynclitism).
- A pH of 7.19 demands immediate action β not continued observation.
Conditions for operative delivery: fully dilated cervix, engaged head, known position, no CPD, consent obtained, skilled operator.
A water supply at a desert outpost is sufficient to last 21 days for a group of 15 people. At the same average rate of consumption per person per day, how many days would that same water supply last for a group of only 9 people?
Total water supply $=$ (people) $\times$ (days) $\times$ (rate per person per day).
Total supply $= 15 \times 21 = 315$ person-days.
For 9 people: days $= \dfrac{315}{9} = 35$ days.
Answer: 35.0 days.
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