Step 1: The Rs. 18,000 was wrongly expensed. Reversing this increases profit: $83{,}600 + 18{,}000 = 1{,}01{,}600$.

Step 2: Now charge the correct depreciation on the van: $18{,}000 \times 25\% = Rs.\ 4{,}500$.

Step 3: Subtract depreciation: $1{,}01{,}600 - 4{,}500 = \mathbf{Rs.\ 97{,}100}$

The net effect is: profit increases by Rs. 18,000 (expense reversed) but decreases by Rs. 4,500 (depreciation charged) — a net increase of Rs. 13,500 over the originally reported profit.

• Fresh air and ventilation
• Clean water
• Efficient drainage
• Cleanliness
• Light (especially sunlight)
• Noise reduction

Statement II is a standard property of definite integrals (proved by substitution $x\to a+b-x$). It is true and is the key tool to evaluate I.

Statement I: Let $I=\int_{\pi/6}^{\pi/3}\dfrac{dx}{1+\sqrt{\tan x}}$. Using Statement II with $a+b=\pi/2$: replace $x$ with $\pi/2-x$: $I=\int_{\pi/6}^{\pi/3}\dfrac{dx}{1+\sqrt{\cot x}}=\int_{\pi/6}^{\pi/3}\dfrac{\sqrt{\tan x}}{1+\sqrt{\tan x}}dx$.

Adding: $2I=\int_{\pi/6}^{\pi/3}1\,dx=\dfrac{\pi}{3}-\dfrac{\pi}{6}=\dfrac{\pi}{6}$, so $I=\dfrac{\pi}{12}$...

Wait: the problem states $I=\pi/6$. $2I=\pi/6$ gives $I=\pi/12$. The stated value $\pi/6$ applies to $2I$. In some versions the statement says the integral equals $\pi/12$. Statement II is the correct explanation for Statement I. Both are true and II explains I.

From the given inequality: $x + 2y > 8$

Multiplying both sides by 2: $2(x + 2y) > 2(8)$

This gives us: $2x + 4y > 16$

So we know that Column A $> 16$, but we cannot determine whether $2x + 4y$ is greater than, less than, or equal to 20 without additional information.

For example:

• If $x = 5, y = 2$: then $x + 2y = 9 > 8$ ✓, and $2x + 4y = 18 < 20$
• If $x = 10, y = 5$: then $x + 2y = 20 > 8$ ✓, and $2x + 4y = 40 > 20$

Since different valid values give different relationships, the answer cannot be determined from the information given.