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Given: Quick (acid-test) ratio $= 2.0$; Current assets $= \text{Rs. }5{,}000$; Inventory $= \text{Rs. }2{,}000$; Prepaid expenses $= 0$. Find the value of current liabilities.
The Quick Ratio formula is:
$\text{Quick Ratio} = \dfrac{\text{Current Assets} - \text{Inventory} - \text{Prepaid Expenses}}{\text{Current Liabilities}}$
$2.0 = \dfrac{5{,}000 - 2{,}000 - 0}{\text{CL}} = \dfrac{3{,}000}{\text{CL}}$
$\text{CL} = \dfrac{3{,}000}{2.0} = \mathbf{Rs.\ 1{,}500}$
The quick ratio excludes inventory and prepaid expenses from current assets since these are less liquid. Dividing quick assets by the ratio gives current liabilities.
Mary purchased a book whose price plus a 4% sales tax equaled the total amount she paid. She gave the cashier a $10 bill and received correct change of less than $3.00. Which of the following statements must be true? Select all that apply.
Let the price of the book $= p$. Total paid $= 1.04p$.
She paid $10 and received change less than $3.00, meaning total paid was more than $7.00:
$1.04p > 7.00 \Rightarrow p > 6.73$
She also received some change, so total paid $< \$10.00$:
$1.04p < 10.00 \Rightarrow p < 9.615$
So $6.73 < p < 9.615$. Now check each statement:
- Statement A: $p < \$9.50$ — Not necessarily, since $p$ can be up to $9.615$. ✗
- Statement B: $p > \$6.90$ — Not necessarily, $p$ can be $6.80$ (giving change $\approx \$2.93 < \$3.00$). ✗
- Statement C: Sales tax $= 0.04p < 0.04 \times 9.615 \approx \$0.385 < \$0.45$. This is always true within the valid range. ✓
- Statement D: Tax $> \$0.50$ would require $p > 12.50$, which is impossible here. ✗
Only Statement C must be true.
In a certain shop, notebooks that normally sell for 59 cents each are on sale at 2 for 99 cents. How much can be saved by purchasing 10 of these notebooks at the sale price?
Normal price for 10 notebooks: $10 \times 59\text{¢} = 590\text{¢} = \$5.90$
Sale: 2 notebooks for 99¢, so 10 notebooks cost $5 \times 99\text{¢} = 495\text{¢} = \$4.95$
Savings $= \$5.90 - \$4.95 = \$0.95$
- \(n \geq 1\)
- \(0 \leq \ell \leq n-1\)
- \(-\ell \leq m \leq +\ell\)
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