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Initial charge (without dielectric):
$Q_0 = C_0 V = 90 \times 10^{-12} \times 20 = 1800\ \text{pC} = 1.8\ \text{nC}$
New capacitance with dielectric:
$C = KC_0 = \frac{5}{3} \times 90 = 150\ \text{pF}$
New free charge:
$Q = CV = 150 \times 10^{-12} \times 20 = 3000\ \text{pC} = 3\ \text{nC}$
Induced charge on dielectric:
$Q_{induced} = Q\left(1 - \frac{1}{K}\right) = 3 \times \left(1 - \frac{3}{5}\right) = 3 \times \frac{2}{5} = 1.2\ \text{nC}$
Pakistan EPI Schedule (current):
| Age | Vaccines |
|---|---|
| Birth | BCG, OPV-0, Hepatitis B (birth dose) |
| 6 weeks | Pentavalent (DTP-HepB-Hib), OPV-1, PCV-1, Rotavirus-1, IPV-1 |
| 10 weeks | Pentavalent-2, OPV-2, PCV-2, Rotavirus-2 |
| 14 weeks | Pentavalent-3, OPV-3, PCV-3, IPV-2 |
| 9 months | Measles-1, Vitamin A (1st dose) |
| 15 months | Measles-2 (MMR) |
Pentavalent vaccine = 5-in-1 vaccine protecting against:
- Diphtheria
- Tetanus
- Pertussis (whooping cough)
- Hep B (Hepatitis B)
- Hib (Haemophilus influenzae type b)
Contraindications: Previous anaphylaxis to vaccine component, progressive neurological disorder (for pertussis component), severe febrile illness (defer, not contraindicate).
Cold chain: Pentavalent stored at \(2{-}8°C\); never frozen (freeze-sensitive).
(Select the best word. Note: two words produce sentences alike in meaning — choose the most accurate.)
Lasswell's formula is one of the most widely cited early models of mass communication. The sociologist Harold Lasswell (1948) proposed analysing mass media by asking five questions, each of which corresponds to a distinct field of scholarly inquiry:
- Who? → Control Research (who owns, controls, and regulates media)
- Says What? → Content Research (what messages are being sent)
- In What Channel? → Medium Research (the technology used to transmit)
- To Whom? → Audience Research (who is receiving the message)
- With What Effect? → Effects Research (what impact does the message have)
Lasswell was primarily concerned with mass communication and propaganda, so his model is designed to direct researchers toward the kind of systematic inquiry needed to understand and evaluate media power.
Compare the two quantities below.
Column A: $(0.82)^2 \cdot (0.82)^3$
Column B: $(0.82)^6$
Using the rule of exponents: $(0.82)^2 \cdot (0.82)^3 = (0.82)^{2+3} = (0.82)^5$.
Now compare $(0.82)^5$ vs $(0.82)^6$.
Since $0 < 0.82 < 1$, multiplying by $0.82$ makes the number smaller. Therefore $(0.82)^5 > (0.82)^6$.
Column A is greater.
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