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Percentage \(= \dfrac{21}{25} \times 100 = 84\%\)
The textbook describes two main types of newspaper advertising:
- Classified Advertisements: Brief, text-only ads, usually confined to a single column. They are the simplest form of print advertising — historically used for job vacancies, property rentals, for-sale items, personal notices, and service listings. The term “classified” comes from their organisation into categories (jobs, real estate, vehicles, etc.).
- Display Advertisements: Larger, visually designed ads that can span multiple columns. They include graphics, logos, photographs, colour, and creative layouts designed to attract attention. Display ads are the dominant format for branding and promotional campaigns. The first multi-column display ads in the U.S. were used to promote transcontinental railroad bonds in the 1860s.
The textbook notes that newspapers typically charge display ads in advance, but advertising agencies are given 90-day credit terms. Premium placement (front page, specific positions) can cost up to 400% more than standard rates.
The total of Konrad's purchases ledger balances was $57,400. Later, these errors were found:
| Discount allowed overcast in cash book | $2,000 |
| Returns outwards omitted in a supplier's account | $350 |
| Payments to trade payables undercast in cash book | $137 |
| Purchases journal overcast | $500 |
What is the corrected total of the trade payables balances?
Only errors affecting individual supplier accounts change the purchases ledger total.
1. Returns outwards omitted: $57,400 - $350 = $57,050.
The others (Discount allowed, payments undercast in cash book, journal overcast) affect the Control Account or other ledgers, but not the individual ledger balances until corrected there.
Two cars P and Q start simultaneously from the same point. Their positions are $x_P(t) = at + bt^2$ and $x_Q(t) = ft - t^2$. At what time do they have equal velocities?
$v_P = a + 2bt$, $\quad v_Q = f - 2t$
Setting equal: $a + 2bt = f - 2t \Rightarrow 2t(b+1) = f-a \Rightarrow t = \mathbf{\dfrac{f-a}{2(1+b)}}$
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