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Let $A$ be a $2\times2$ symmetric matrix with integer entries. If the sum of the diagonal elements of $A^2$ equals 1, find the number of such possible matrices.
Let $A=\begin{pmatrix}a&b\\b&c\end{pmatrix}$. Then $A^2=\begin{pmatrix}a^2+b^2&ab+bc\\ab+bc&b^2+c^2\end{pmatrix}$.
Sum of diagonal of $A^2 = a^2+2b^2+c^2 = 1$.
Since $a,b,c$ are integers and $a^2+2b^2+c^2=1\geq0$: $b=0$ (since $2b^2\leq1$ with integer $b$ forces $b=0$), then $a^2+c^2=1$.
Solutions: $(a,c)\in\{(1,0),(β1,0),(0,1),(0,β1)\}$ and $b=0$: 4 matrices. But we should check $b=\pm1$: $2(1)=2>1$, not possible. Hmm β that gives only 4. But checking $b=0$, $a^2+c^2=1$: integer solutions are $(\pm1,0)$ and $(0,\pm1)$ β exactly 4 pairs, each with $b=0$. So $\mathbf{4}$ matrices... but wait: $b$ can also vary if we allow it. Total = $\mathbf{4}$ matrices.
Persistent Occiput Posterior (POP) position is a common cause of prolonged second stage and arrest of descent. In OP position:
- The fetal head presents with a larger diameter to the pelvis: occipito-frontal diameter \(\approx 11.5\,\text{cm}\) vs. sub-occipito-bregmatic \(9.5\,\text{cm}\) in OA
- Internal rotation from OP to OA requires \(135Β°\) rotation (vs. \(90Β°\) from OT, \(45Β°\) from OA)
- Causes: anthropoid/android pelvis, deflexed head
Management options:
- Manual rotation to OA (Barton's maneuver)
- Expectant management if maternal/fetal condition good
- Instrumental delivery: forceps (Kielland's rotational forceps) or rotational vacuum
- Cesarean section if rotation fails or fetal distress
CPD is less likely in a multigravida who delivered previously without CPD. Hypotonic labor would show weak contractions on partograph/CTG.
#,##0.00;-#,##0.00;0;@, the first part applies to positive values.
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