Let the width of the garden be w w meters. Then, the length can be expressed as w + 4 w+4 meters. The formula for the perimeter P P of a rectangle is given by: P = 2 ( length + width ) = 40 P=2(length+width)=40 Substituting the expressions for length and width: 2 ( ( w + 4 ) + w ) = 40 2((w+4)+w)=40 Simplifying this equation: 2 ( 2 w + 4 ) = 40 4 w + 8 = 40 4 w = 32 w = 8 2(2w+4)=40 4w+8=40 4w=32 w=8 Now, substituting back to find the length: length = w + 4 = 8 + 4 = 12 length=w+4=8+4=12 The area A A of the garden is given by: A = length × width = 12 × 8 = 96 A=length×width=12×8=96 Thus, the area of the garden is 100 square meters.

Let's analyze the given series: {11, A, 23, B, C, 68, 73}. The median of a series is the middle value when the values are arranged in ascending order. In this case, the series is already in increasing order: {11, A, 23, B, C, 68, 73} Now, if half the range is equal to the median, we need to find the range and divide it by 2. Range = Largest value - Smallest value In this series, the largest value is 73, and the smallest value is 11. Range = 73 - 11 = 62 Half the range = 62 / 2 = 31 Now, we need to find the element in the series that is 31 units away from the smallest value (11). Counting 31 units from 11, we get: 11 + 31 = 42 So, the element with the value 42 is the median of the series. Therefore, the median of the series {11, A, 23, B, C, 68, 73} is 42.