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A particle is thrown vertically upward. Its speed at half the maximum height is $10\text{ m/s}$. The maximum height attained is ($g = 10\text{ m/s}^2$):
Let maximum height $= H$. At height $H/2$, velocity $= 10\text{ m/s}$.
Using $v^2 = u^2 - 2g\cdot\dfrac{H}{2}$: $100 = u^2 - gH$
At max height: $0 = u^2 - 2gH \Rightarrow u^2 = 2gH$
Substituting: $100 = 2gH - gH = gH \Rightarrow H = \dfrac{100}{10} = \mathbf{10\text{ m}}$
- $Na^{+}$ (Charge: +1)
- $Ba^{2+}$ (Charge: +2)
- $Al^{3+}$ (Charge: +3)
Draft loss for year: $320. Adjustments needed: (1) Irrecoverable debts of $930 recovered; (2) Existing allowance $520, required allowance = 5% of trade receivables $9,600. What is the revised profit or loss?
Option D (Profit of $650) is correct.
Recovery of debt: +$930
Required allowance = 5% × $9,600 = $480; Reduction = $520 − $480 = +$40
Revised = −$320 + $930 + $40 = +$650 profit
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